Noncompetitive inhibition at Vmax

 


No inhibitor present

When there is not inhibitor present all of the enzyme is bound to substrate at the Vmax

 

 

 

 

 

 

 

When noncompetitive inhibitor is present

When there is noncompetitive inhibitor present, some of the enzyme will be bound to inhibitor (an be inactive) and some of the enzyme will be bound to substrate and be active

 

 

 

The Vmax of the reaction with noncompetitive inhibitor will be lower than the reaction without noncompetitive inhibitor because with the inhibitor present there is less active enzyme than in its absence.


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