Noncompetitive inhibition at Vmax
No inhibitor present
When there is
not inhibitor present all of the enzyme is bound to substrate at the Vmax
When noncompetitive inhibitor is present
When there is
noncompetitive inhibitor present, some of the enzyme will be bound to inhibitor
(an be inactive) and some of the enzyme will be bound to substrate and be
active
The Vmax of the reaction with noncompetitive inhibitor will be lower
than the reaction without noncompetitive inhibitor because with the inhibitor
present there is less active enzyme than in its absence.