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The
most obvious way for a silicon tetrahedron to reduce its negative charge would be
to bond with positive ions (cations)
(i.e., form an
ionic bond).
If
you need to review your definitions of chemical bonding...
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For
example, a tetrahedron could bond with two Mg2+ ions.
This
balanced arrangement (Mg2SiO4) is actually the
mineral forsterite.
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However,
because silicon and oxygen are so much more abundant than the cations such
as magnesium, we would expect to run out of positive ions long before we
used up the silicon and oxygen!
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So
if there is a surplus of silica tetrahedra...
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...What
if tetrahedra bonded together by sharing an oxygen ion between them (i.e.,
covalently bonding
with another tetrahedron)?...
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...Or
by sharing more than one oxygen?
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Let's
analyze the pattern... |
Case 1: SiO44-
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1
tetrahedron
No
shared oxygens |
1
Si
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4-
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-4
/ Si
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Case 2: Si2O76-
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2
tetrahedra
1
shared
oxygen/tetrahedron |
2
Si
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6-
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-3
/ Si
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Case 3: Si5O1312-
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5
tetrahedra
1
or 2 shared oxygens/tetrahedron |
5
Si
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12-
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-2.4
/ Si
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As
more oxygens are shared between tetrahedra, the overall charge per
tetrahedron decreases.
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In fact, if a tetrahedron
shared each of it's 4 oxygens with neighboring tetrahedra (i.e., kept half
for itself and gave half to each neighbor), then it would have no charge
(neutral).
The
balanced arrangement SiO2 is actually the
mineral quartz, one of the most common minerals in the continental crust.
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