Chapter 2
#6: (a) Distance = 14.1 m, Displacement = 9.0 m
      (b) Increases
      (c) Decreases
      (d) Distance = 28.3 m, Displacement = 0.
#18) vavg = 64 km/hr
#104)(a) 1.87 m/s
      (b) 1.01 m/s
A) vA = 2.5 m/s,vB = 4.0 m/s, vC = 3.25 m/s
C) vA = 2.5 m/s,vB = 1.67 m/s, vC = 2.0 m/s
      [{vA + vB}/2 = 2.08 m/s]
D) 66.0 km/hr
E) After t = 0 B is ahead.
      They meet at t = 50 s, x = 7,750 m.
      A does not catch up in 1500 m, so B wins.
Chapter 3
#66) 1.68 km, 61 deg. S of W.
#72) 3.73 m/s2
A) A+B: Around 3.8, 10 deg. E of N
      A-B: Around 2.5, 20 deg. W of N
      A-2B: Around 1.5, 45 deg. W of N
B) a ~ 5.1 m/s2
C) (i) 2.8 m/s2, 225 deg.
      (ii) 2.0 m/s2, 270 deg.
      (iii) 0.
D) t = 2, x = 7.7, y = 6.71, r = 10.1, beta = 41 deg.
t = 4, x = 12.4, y = 8.42, r = 15.0, beta = 34 deg.
Chapter 4
A) R = 21.8 m
Chapter 5
#4) 40.6 kg
#40) 1.9 m/s2, up; velocity not determined.
Chapter 6
A) x = 10 deg., sinx/x = .9950
x = 5 deg., sinx/x = .9987
x = 2 deg., sinx/x = .9997
x = 1 deg., sinx/x = 1.0000
C) a = 2.17 m/s2; T = 21.4 N
Chapter 8
#4) minus 1100 J, independent of mass
#30) 3,220 N/m; 0.4 m/s
#36) v = {[2(m2-m1)gh]/[m2+m1]}1/2
       v= 1.10 m/s
#58) 10.3 degrees
#96) h > (5/2)r
A) 0.88 m/s
B) 0.92 m/s
Chapter 9
#4) v = -0.69 m/s; KE = 0.40 J
#30) 2.93 m/s
#34) 0.035 m
#42) left to right: (1/3)v0, (4/9)v0, (16/9)v0
#46) 0.58 m
#50) ycm = -(1/10)L
C) v1 = 2.5 m/s; v2 = 12.5 m/s; f1 = 0.062; f2 = 0.938
D) 2.40 s after the first collision
E)    (a) v = 2.70 m/s; angle = -14.8 degrees
       (b) 48%
F)    (a) 0.94 m/s, to the right
       (b) fraction = 0.67
G)    (a) 1.05 m/s; 18 degrees below positive x axis.
       (b) fraction = 0.63
Chapter 10
#8) 7.27 X 10-5 rad/s
#30) 1.44 X 10-4 m/s
#70) 2.1 kg
#110) (a) 357 N; (b) 918 N; (c) 638 N
A) 0.105 rad/s; 1.75 X 10-3 rad/s
B) 0.01 kg
C) v = 1.60 m/s; a = 1.48 m/s2
D) 0.441 m/s
E) 463 m/s
F) 2.99 X 104 m/s
G) Diagram (a)
Chapter 11
#26) 42.0 kg; 0.74 m
#28) (a) 2.3 m; (b) 1.56 m; (c) no change
A)    (a) 9.38 X 1041 kg-m2/s
       (b) 1.93 X 1043 kg-m2/s
      (c) ratio = 21
B) 1.94 rev/s
C) Fraction of KE lost = 50%
D) All KE lost
F) angular freq. = 8.6 rad/s; freq. = 1.4 rev/s
Chapter 12
Note: Answers in the textbook for problems 9, 15 and 35 are not correct.
#9) 4.79 X 1020 N; 24.4 degrees
#15) 2.64 X 103 km
#35) (a) satellite 2; (b) 5.59 X 103 m/s; (c) 4.56 X 103 m/s
A) 726 N
B) 9.08 m/s2
C) 1.62 m/s2
D) 0.037 m/s2
F) vesc = [2Gmmoon/rmoon]1/2; 2.36 X 103 m/s
G) vorbit = 7.90 X 103 m/s; 1.4 hours
H) mass = 6.02 X 1024 kg
I) 500 km
J) 5.73 X 103 m/s
K) R = 2GM/c2
L) 14.7 km; density = 7.5 X 1017 kg/m3
M) 1.8 X 1039 kg; 109 stars
O) r = 4.22 X 107 m; r/RE = 6.6
Chapter 13
B) -.26, -.48, -.65, -.76
-.64, -.23, +.27, +.66, +.63
C) x: .2, 0, -.2, 0, .2, 0
v: 0, -1.05, 0, +1.05, 0, -1.05
F) 0.39 s
G) T = 2(pi)[m/(k1 + k2)]1/2
H) x: 3.66 m, -4.95 m, -4.94 m
t: 1.04 s
I) vavg = -.08 m/s; k = 1.97 N/m; vinst = -0.126 m/s
J) v = 0.155 m/s for x = +1 and -1; x = +0.0205 m
K) T = 5070 s = 1.41 hours
Chapter 14
#14) 0.19 s
#44) 14.6 m/s
Chapter 15
#8) 1.53 X 106 Pa
#48) 20% under water
D) cylinder moves up
E) 4.0 cm
F) density = 15,000 kg/m3
Chapter 16
#36) 120 degrees Celsius
#38) 24.0 degrees C.
#76) a) Probably aluminum (c = 892 J/kg-K)
      b) 54.4 J/s
#88) 3 seconds before 10 AM
A) 12 cm, 1 degree = 1 mm
Chapter 17
#58) 2.2 kg
#60) a) No ice remains, final temp. = 30 deg.
      b) Mass is doubled.
#6) 14%
#14) a) 3.9 X 1024
      b) 1.26; cubed root of 2
#20) 160 kPa
#26) 20 K
#28)a) 4.0 X 106 Pa
      b) 1.18 X 10-20 J
      c) Pressure is half; kinetic energy the same.
A) p = 13.5 kPa; pressure multiplied by 4
B) 14.7 kPa
C) p =(1/3)(NA/V) [nAmAvA2 + nBmBvB2]
D) a) 0.833
      b) 1.12
      c) 1.00
E) "p" = (1/2)[N/(area)]mv2
F) 0.8 moles, 25.6 g
G) density of steam = 0.589 kg/m3; ice/steam = 1,562; s/a = 11.6
H) 1.91
I) N = 336; speed of pellets decreases because of gravity
Chapter 18
#8) a) 468 K; b) decreases
#52) a) 0.88
      b) 300 J
      c) 8.3
#66) 1.12 X 104 J/K
#70) 1.12 X 103 J/K
#72) 2.6 J/K
A) 12.8 deg. C
B) 231 J/kg-C
C) 75 deg. C
D) 13.3 deg. C
E) 20 g
F) 724 J/kg-C
G) 356 J/kg-C
H) a) L = 0.622 m; Wf = -1.92m; mu = 0.411
      b) Q = 0; W = 0; change in macro energy = -1.92m; change in micro energy = +1.92m; change in temp. = 0.00192 deg. C
I) WP = 50 J; Q = 0; change in macro energy = +22.5 J; change in micro energy = + 27.5 J
J) 2.6 J/K {Assumption: Cube is 3 cm on a side.}
K) 4.0 J/K {Assumptions: Coffee is 95 deg. C, milk is 4.4 deg. C (40 deg. F); coffee is 8 ounces, milk is 1 ounce.}
L) Q1 = 104 J;
Q2 = 3.15 X 104 J
eff = 14%